x=(1/20)y^2

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Solution for x=(1/20)y^2 equation: 


x in (-oo:+oo)

x = (1/20)*y^2 // - (1/20)*y^2

x-((1/20)*y^2) = 0

x+(-1/20)*y^2 = 0

x-1/20*y^2 = 0 // + -1/20*y^2

x = -(-1/20*y^2)

x = 1/20*y^2

x = 1/20*y^2

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